# Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams

Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams |

**1. If 11x - 13 = -2x + 78, then x = ?**

A. 7

B. 8

C. 6

D. 4

**2. The value of x + y in the solution of the equations x/4 + y/3 = 5/12 and x/2 +y = 1**

A. 1/2

B. 2

C. 5/2

D. 3/2

**3. If 2x + 3y = 12 and 3x - 2y = 5, then x and y must have the value:**

A. 2 and 3

B. 2 and -3

C. 3 and -2

D. 3 and 2

**4. The height of an equilateral triangle whose perimeter is 27 cm. is :**

A. 9/2 √3 cm

B. 9/2 cm

C. 9 cm

D. none of these

**5. Find the distance between the two parallel sides of a trapezium if the area of the trapezium is 250 sq.m and the two parallel sides are equal to 15 m and 10 m respectively.**

A. 15 m

B. 20 m

C. 25 m

D. 22 m

**6. The length of a rectangle is increased by 60%. By what percent would the width be decreased so as to maintain the same area?**

A. 37 1/2%

B. 60%

C. 75%

D. 120%

**7. The ratio between the length and width of the rectangular field is 3 : 2. If only length is increased by 5 m. The new area of the field is 2600 m^2. What is the width of the rectangular field?**

A. 60 m

B. 50 m

C. 40 m

D. 65 m

**8. A regular polygon with n sides has interior angles measuring 178° . What is the value of 180/n?**

A. 1

B. 2

C. 3

D. 4

**9. Five equal cubes, each of side 5 cm, are placed adjacent to each other. The volume of the new solid formed will be**

**A.125 cm^3**

B.625 cm^3

C.15525cm^3

D.1225cm^3

**10. One of sides of a right-angled triangle is twice the other, and the hypotenuse is 10 cm. The area of the triangle is:**

A .20 cm

^{2 }

B .33 1/3 cm

^{2}
C .40 cm

^{2 }
D. 50 cm

^{2}

**Answers with explanation :**

**1.A**

**2.D**

**3.D**

4.A 3a = 27

a = 9cm

5.B Area = 1/2(sum of parallel sides) * (distance between them)

=> 250 = 1/2(15 + 10) * h

6.A Let length = width = 100m

If length = 160m, then let width = x m

s.t. 160x = 10000

=> x = 10000/160 = 1000/16 = 62 1/2

a = 9cm

**height = √3/2 a = 9/2 √3**5.B Area = 1/2(sum of parallel sides) * (distance between them)

=> 250 = 1/2(15 + 10) * h

**=> h = 20m**6.A Let length = width = 100m

If length = 160m, then let width = x m

s.t. 160x = 10000

=> x = 10000/160 = 1000/16 = 62 1/2

**so width is reduced to 37 1/2 %**
7.C Let length = 3x, then width = 2x

so (3x +5)2x = 2600 ⇒(3x + 5)x = 1300

We, go through the options 2x = 40 ⇒x = 20 which satisfy the above equation

so (3x +5)2x = 2600 ⇒(3x + 5)x = 1300

We, go through the options 2x = 40 ⇒x = 20 which satisfy the above equation

**so Width = 2x = 40m**
8.Exterior angle = 180 – 178 = 2°

**⇒**

**360/n = 2 so 180/n = 1**

9.The new solid formed is a cuboid of
length 25 cm, breadth 5 cm and height 5 cm

Volume = (25x5x5)cm^3

Volume = (25x5x5)cm^3

**‹=›625cm^3**
10. A

Let the sides be a cm and 2a cm

Then, a

^{2}+ (2a)^{2 }= (10)^{2}
5 a

^{2}= 100
a

^{2 }= 20 cm^{2}**Area = (1/2 *a *2a) = a**

^{2}= 20 cm^{2}
Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams
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