Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams


Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams
Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams 

1. If 11x - 13 = -2x + 78, then x = ?
A. 7
B. 8
C. 6
D. 4

2. The value of x + y in the solution of the equations x/4 + y/3 = 5/12 and x/2 +y = 1
A. 1/2
B. 2
C. 5/2
D. 3/2

3. If 2x + 3y = 12 and 3x - 2y = 5, then x and y must have the value:
A. 2 and 3
B. 2 and -3
C. 3 and -2
D. 3 and 2


4. The height of an equilateral triangle whose perimeter is 27 cm. is :
A. 9/2 √3  cm
B. 9/2 cm  
C. 9 cm 
D. none of these

5. Find the distance between the two parallel sides of a trapezium if the area of the trapezium is 250 sq.m and the two parallel sides are equal to 15 m and 10 m respectively.
A. 15 m  
B. 20 m  
C. 25 m 
D. 22 m

6. The length of a rectangle is increased by 60%. By what percent would the width be decreased so as to maintain the same area?
A. 37 1/2%  
B. 60%  
C. 75% 
D. 120%

7. The ratio between the length and width of the rectangular field is 3 : 2. If only length is increased by 5 m. The new area of the field is 2600 m^2. What is the width of the rectangular field?
A. 60 m  
B. 50 m  
C. 40 m 
D. 65 m

8. A regular polygon with n sides has interior angles measuring 178°  . What is the value of 180/n?
A. 1
B. 2
C. 3
D. 4

9. Five equal cubes, each of side 5 cm, are placed adjacent to each other. The volume of the new solid formed will be
A.125 cm^3
B.625 cm^3
C.15525cm^3
D.1225cm^3

10. One of sides of a right-angled triangle is twice the other, and the hypotenuse is 10 cm. The area of the triangle is:
A .20 cm2                        
B .33 1/3 cm2
C .40 cm2                        
D. 50 cm2

Answers with explanation :
1.A 

2.D

3.D

4.A 3a = 27 
a = 9cm 
height = √3/2 a = 9/2 √3

5.B Area = 1/2(sum of parallel sides) * (distance between them) 

=> 250 = 1/2(15 + 10) * h 
=> h = 20m

6.A Let length = width = 100m 
If length = 160m, then let width = x m
s.t. 160x = 10000 
=> x = 10000/160 = 1000/16 = 62 1/2 
so width is reduced to 37 1/2 % 

7.C Let length = 3x, then width = 2x 
so (3x +5)2x = 2600
(3x + 5)x = 1300 
We, go through the options   2x = 40
x = 20 which satisfy the above equation 
so Width = 2x = 40m

8.Exterior angle = 180 – 178 = 2°
360/n = 2 so 180/n = 1

9.The new solid formed is a cuboid of length 25 cm, breadth 5 cm and height 5 cm
Volume = (25x5x5)cm^3
‹=›625cm^3

10.  A
Let the sides be a cm and 2a cm
Then, a2 + (2a)= (10)2
5 a2= 100
a= 20 cm2

Area = (1/2 *a *2a) = a2= 20 cm2






Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams Quest For Railway- 2016 :: Quantity Question For RRB, SSC, And All Competitive Exams Reviewed by SSC-IBPS on 14:03:00 Rating: 5
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