QUEST FOR CLERK:: MIXED ARITHMETIC QUESTIONS FOR IBPS CLERK MAINS

                                          
QUEST FOR CLERK:: MIXED ARITHMETIC QUESTIONS FOR IBPS CLERK MAINS
QUEST FOR CLERK:: MIXED ARITHMETIC QUESTIONS FOR IBPS CLERK MAINS 
1. ? % of 824 + 244 = 1480
1) 140
2) 150
3) 100
4) 180
5) 120


2. 24.5 × 8.4 × 16 = ?
1) 3292.8
2) 3492.8
3) 3294.8
4) 3192.8
5) 3094.8

Directions: In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer:
1) if x > y 
2) if x >= y 
3) if x < y
4) if x <= y 
5) if x = y or relationship between x and y cannot be determined.

3.
I. 2x^2 + 13x + 20 = 0
II. 2y^2 – 3y – 35 = 0

4.
I. 12x^2 – 41x + 35 = 0
II. 4y^2 – 17y +15 = 0

5.
I. 4x^2 – 4 = 60
II. 3y^2 + 3 = 51

6.
I. 28x^2 – 9x – 9 = 0
II. 7y^2 + 24y + 9 = 0

Directions: In the following number series one number is wrong. Find out the wrong number.

7. 16, 40, 100, 250, 630
1) 630
2) 100
3) 250
4) 40
5) 16

8. 21, 48, 162, 969, 7748
1) 7748
2) 21
3) 969
4) 48
5) 162

9. 118, 239, 96, 264, 68, 293
1) 293
2) 264
3) 96
4) 68
5) 239

10. 128, 320, 1120, 5040, 27720, 180190
1) 27720
2) 5040
3) 320
4) 1120
5) 180190

ANSWERS WITH EXPLANATION

1. 2
2. 1
3. 5
I. 2x^2 + 8x + 5x + 20 = 0
 x = -5/2,– 4Þ(2x + 5) (x + 4) = 0


II. 2y^2 – 10y + 7y – 35 = 0
 y = -7/2, 5Þ(2y + 7) (y – 5) = 0


Relationship between x and y does not exist.

4. 5;
I. 12x^2 – 20x – 21x + 35 = 0
(4x –7) (3x – 5) = 0
x = 7/4, 5/3
 (4y – 5) (y – 3) = 0ÞII. 4y^2 – 12y – 5y + 15 = 0

y = 5/4, 3
Relationship between x and y does not exist

5.5;
I. 4(x^2 – 1) = 60 x^2 – 1 = 15
x = +/- 4

II. 3(y^2 + 1) = 51 y^2 + 1 = 17
y = +/- 4
Hence x = y

6. 2;
I. 28x^2 – 21x + 12x – 9 = 0 (7x + 3) (4x – 3) = 0
x = -3/7, 3/4

II. 7y^2 + 21y + 3y + 9 = 0 (7y + 3) (y + 3) = 0
y = -3/7,–3

7. 1
16 * 5/2 = 40  40 * 5/2 = 250

250 * 5/2 = 625 not equal to 630

Hence there should be 625 in place of 7630

8. 4:
The series is:  21 × 2 – 1 = 41 not equal to 48

41 × 4 – 2 = 162 , 162 × 6 – 3 = 969
969 × 8 – 4 = 7748


Hence, there should 41 in place of 48.

9. 3;
The series is: 118 + (11)^2 = 239

239 – (12)^2 = 95 not equal to 96
95 + (13)^2 = 264
264 – (14)^2 = 68
68 + (15)^2 = 293
Hence there should be 95 in place of 96.

10. 5
The series is
128 * 5/2 = 320
320 * 7/2 = 1120
1120 * 9/2 = 5040
5040 * 11/2 = 27720
27720 * 13/2 = 180180 not equal to 180190



QUEST FOR CLERK:: MIXED ARITHMETIC QUESTIONS FOR IBPS CLERK MAINS QUEST FOR CLERK:: MIXED ARITHMETIC QUESTIONS FOR IBPS CLERK MAINS Reviewed by SSC-IBPS on 13:53:00 Rating: 5
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